Forum newsfeeds |  | | Notices | You are welcome to answer questions posted in the Ask a Teacher forum as long as your suggestions, help, and advice reflect a good understanding of the English language. If you are not a teacher, you will need to state that clearly at the top of your post. Please note, all posts are moderated by our in-house language experts, so make sure your suggestions, help, and advice house the kind of information an international language teacher would offer. If not, and your posts do not contribute to the topic in a positive way, they will be subject to deletion. | 
29-Aug-2008, 10:53
| | Member | | Join Date: Feb 2008 Country: China
Posts: 245
Current Location: Beijing First Language: Chinese Member Type: Student or Learner Thanks: 178
Thanked 1 Time in 1 Post
| | median Hi, "The data showed that respondents with the most positive attitudes survived a median of 22 years after their initial interview, "
I hope someone could have a look for me. I do not think I get this sentence exactly, does it mean - "Respondents with the most positives attitudes survived in the middle of 22 years (around 11 years) after their initial interview." Or " Around a half of these respondents (around 320 people) with the most positive attitudes survived 22 years after their initial interview." The word "median" here refers to the amount of the time or the respondents ?
What does this sentence mean?
Thanks for your help.
... The researchers found that people who view aging positively live longer than people who view it negatively. This study began 26 years go and took place in a small town in the Midwest. The participants were 640 men and women who were 50 to 90 years old at the the time. The subjects were asked to agree or disgree with statements about aging, like "As you get older, you become less useful" and "Older people can't learn new skills." The data showed that respondents with the most positive attitudes survived a median of 22 years after their initial interview, while those with negative views lives just 15 years - a difference of seven years. | 
29-Aug-2008, 11:00
|  | Key Member | | Join Date: Apr 2008 Country: England
Posts: 2,370
Current Location: France First Language: English Member Type: English Teacher Thanks: 129
Thanked 1,096 Times in 995 Posts
| | Re: median Quote:
Originally Posted by XINLAI-UE Hi, "The data showed that respondents with the most positive attitudes survived a median of 22 years after their initial interview, "
I hope someone could have a look for me. I do not think I get this sentence exactly, does it mean - "Respondents with the most positives attitudes survived in the middle of 22 years (around 11 years) after their initial interview." Or " Around a half of these respondents (around 320 people) with the most positive attitudes survived 22 years after their initial interview." The word "median" here refers to the amount of the time or the respondents ?
What does this sentence mean?
Thanks for your help.
... The researchers found that people who view aging positively live longer than people who view it negatively. This study began 26 years go and took place in a small town in the Midwest. The participants were 640 men and women who were 50 to 90 years old at the the time. The subjects were asked to agree or disgree with statements about aging, like "As you get older, you become less useful" and "Older people can't learn new skills." The data showed that respondents with the most positive attitudes survived a median of 22 years after their initial interview, while those with negative views lives just 15 years - a difference of seven years. | It means that they survived an average of 22 years. | | The Following User Says Thank You to bhaisahab For This Useful Post: | | 
29-Aug-2008, 15:52
|  | Key Member | | Join Date: Jun 2008 Country: Australia
Posts: 3,187
Current Location: Brisbane First Language: English Member Type: Academic Thanks: 46
Thanked 1,388 Times in 1,279 Posts
| | Re: median Quote:
Originally Posted by XINLAI-UE ... The researchers found that people who view aging positively live longer than people who view it negatively. This study began 26 years go and took place in a small town in the Midwest. The participants were 640 men and women who were 50 to 90 years old at the the time. The subjects were asked to agree or disgree with statements about aging, like "As you get older, you become less useful" and "Older people can't learn new skills." The data showed that respondents with the most positive attitudes survived a median of 22 years after their initial interview, while those with negative views lives just 15 years - a difference of seven years. | The "median" is one form of "average". More commonly, the "mean" is taken as the average.
The "mean" is all the values summed, then divided by the total number.
The "median" is the number such that 50% values are above and 50% below (approximately)
The median is often a better measure if there are extremes in the series.
For example, comparing incomes, here are five annual incomes for some teachers:
20,000; 25,000; 22,000; 23,000; 100,000.
The mean income is: 38,000
The median income is: 23,000
The median is a better indication of what people would call the "average" income.
The media often misuse these concepts, for example saying "The average income of teachers is 38,000. What are they complaining about?" But this is only because one teacher makes 100,000. They should say if they are quoting the mean or the median. | | The Following User Says Thank You to Raymott For This Useful Post: | | 
30-Aug-2008, 11:36
| | Member | | Join Date: Feb 2008 Country: China
Posts: 245
Current Location: Beijing First Language: Chinese Member Type: Student or Learner Thanks: 178
Thanked 1 Time in 1 Post
| | Re: median [quote=Raymott;344783]The "median" is one form of "average". More commonly, the "mean" is taken as the average.
The "mean" is all the values summed, then divided by the total number.
The "median" is the number such that 50% values are above and 50% below (approximately)
Hi, Raymott,
Thanks for your reply.
I have a question. In this case, "median" can be taken as "average", but there is a little difference between them. I mean, more specifically, "median" refers to the middle value of these numbers, like you say:The "median" is the number such that 50% values are above and 50% below (approximately), so the median of these teachers' income is 23,000.
But "average" means the result of adding numbers together to find a total, and then dividing the total by the number of amounts, so the average of these teachers' income if 38,000.
So, "median" and "average" are a little different, and I think it is better for us to take "middle value" instead of taking "average" in this case. I mean, I should get this like, The data showed that respondents with the most positive attitudes survived a median (middle value) of 22 years after their initial interview.
Am I getting this in a correct right way?
In the end, there is a final question about your example.
For example, comparing incomes, here are five annual incomes for some teachers:
20,000; 25,000; 22,000; 23,000; 100,000.
The mean income is: 38,000
The median income is: 23,000 (How do you know the result of this one is 23,000? I did not work out what the method is, could you teach and tell me how to get the median of the numbers, thanks a lot!) | 
30-Aug-2008, 12:37
|  | Moderator | | Join Date: Oct 2006 Country: UK
Posts: 16,781
Current Location: UK First Language: English Member Type: Other Thanks: 5
Thanked 3,906 Times in 3,669 Posts
| | Re: median So, "median" and "average" are a little different, and I think it is better for us to take "middle value" instead of taking "average" in this case. I mean, I should get this like, The data showed that respondents with the most positive attitudes survived a median (middle value) of 22 years after their initial interview.
Am I getting this correct?
incomes for some teachers:
20,000; 25,000; 22,000; 23,000; 100,000.
The mean income is: 38,000
The median income is: 23,000 (How do you know the result of this one is 23,000? I did not work out what the method is, could you teach and tell me how to get the median of the numbers, thanks a lot!) You remove the lowest and the highest figures [20K and 100K], add the remaining figures together and divide by the number of sums involved. | | The Following User Says Thank You to Anglika For This Useful Post: | | 
30-Aug-2008, 19:20
|  | Key Member | | Join Date: Jun 2008 Country: Australia
Posts: 3,187
Current Location: Brisbane First Language: English Member Type: Academic Thanks: 46
Thanked 1,388 Times in 1,279 Posts
| | Re: median Quote:
Originally Posted by Anglika You remove the lowest and the highest figures [20K and 100K], add the remaining figures together and divide by the number of sums involved. | Well, no. That just gives you another mean without the first and last values.
Generally, to get the median (these days) you put all your values in Excel or another spreadsheet, sort them, count them (n = 5) and take the ((n+1)/2)th value (3) (the middle value). You don't need to remove any. | 
31-Aug-2008, 00:05
|  | Key Member | | Join Date: Jun 2008 Country: Australia
Posts: 3,187
Current Location: Brisbane First Language: English Member Type: Academic Thanks: 46
Thanked 1,388 Times in 1,279 Posts
| | Re: median Quote:
20,000; 25,000; 22,000; 23,000; 100,000.
The mean income is: 38,000
The median income is: 23,000 (How do you know the result of this one is 23,000? I did not work out what the method is, could you teach and tell me how to get the median of the numbers, thanks a lot!) | Or you could do it Anglika's way (some computers probably use this algorithm). But you have to keep taking values away.
Input: array of values. Ouput: median
Until the number of values is 2 or fewer {
.... Remove the highest value;
.... Remove the lowest value;
} // This loops until 1 or 2 values remain
If one value remains, return that value as median
else if 2 values remain, return (val1+val2)/2 as median.
Stop. | 
31-Aug-2008, 00:08
| | Member | | Join Date: Feb 2008 Country: China
Posts: 245
Current Location: Beijing First Language: Chinese Member Type: Student or Learner Thanks: 178
Thanked 1 Time in 1 Post
| | Re: median Quote:
Originally Posted by Raymott Well, no. That just gives you another mean without the first and last values.
Generally, to get the median (these days) you put all your values in Excel or another spreadsheet, sort them, count them (n = 5) and take the ((n+1)/2)th value (3) (the middle value). You don't need to remove any. | Hello, Raymott,
It is good to see you, thank you.
"count them (n = 5) and take the ((n+1)/2)th value (3) (the middle value). "
I do not get this one, so I was wondering if you could offer me some explanation with one example, may be we can take the Teacher's Income as one, do we ? | 
31-Aug-2008, 00:46
|  | Key Member | | Join Date: Jun 2008 Country: Australia
Posts: 3,187
Current Location: Brisbane First Language: English Member Type: Academic Thanks: 46
Thanked 1,388 Times in 1,279 Posts
| | Re: median Quote:
Originally Posted by XINLAI-UE Hello, Raymott,
It is good to see you, thank you.
"count them (n = 5) and take the ((n+1)/2)th value (3) (the middle value). "
I do not get this one, so I was wondering if you could offer me some explanation with one example, may be we can take the Teacher's Income as one, do we ?  | Um, that was an example of the teachers income.
Here they are sorted from smallest to largest:
20,000; 22,000; 23,000; 25,000; 100,000.
There were 5 values. n= 5. (5+1)/2 = 3, so you take the third value
The third value is 23,000.
If you start with an even number, say 6, you'll get 3.5 (6+1)/2 = 7/2 = 3.5. In this case, you average the 3rd and 4th values (3rd value + 4th value) / 2.
If you have 1000 values, you take the 1001/2 = 500.5th, which the (500th + 501st) / 2. | | The Following User Says Thank You to Raymott For This Useful Post: | | 
31-Aug-2008, 04:48
| | Member | | Join Date: Feb 2008 Country: China
Posts: 245
Current Location: Beijing First Language: Chinese Member Type: Student or Learner Thanks: 178
Thanked 1 Time in 1 Post
| | Re: median Quote:
Originally Posted by Raymott Um, that was an example of the teachers income.
Here they are sorted from smallest to largest:
20,000; 22,000; 23,000; 25,000; 100,000.
There were 5 values. n= 5. (5+1)/2 = 3, so you take the third value
The third value is 23,000.
If you start with an even number, say 6, you'll get 3.5 (6+1)/2 = 7/2 = 3.5. In this case, you average the 3rd and 4th values (3rd value + 4th value) / 2.
If you have 1000 values, you take the 1001/2 = 500.5th, which the (500th + 501st) / 2. | Hello, Raymott,
Yes, I get it. I also find answer here: Mean, Median, Mode, and Range
It is interesting. It seems I learn a lot of another knowledges from you besides Engish !
Thank you very much! | | Thread Tools | | | | Display Modes | Linear Mode |
Posting Rules
| You may post new threads You may not post replies You may not post attachments You may not edit your posts HTML code is Off | | |
Similar Threads | | Thread | Thread Starter | Forum | Replies | Last Post | | concorete divider | Anonymous | Ask a Teacher | 3 | 13-Jun-2004 01:58 | All times are GMT. The time now is 07:21. |  |