reading numerical formula

[Hazar]

Could you help me read below numerical formula?

6.023×1023


a few angstroms (Å; 1Å=10-8 cm, one hundred millionth of a centimeter)

[abaka]

That looks like Avogadro's constant, or less formally and very often, "Avogadro's Number", with the exponent written without a superscript.


Six point zero two three times ten to the twenty-third.

A few ang-stroms ['æ:ŋgstrəms] or (pseudo-Norwegian) ong-stroms ['ɔ:ŋgstrəms]. In general it's better to pronounce foreign words as naturally as possible in English. That way, neither the English nor, more importantly, the non-English pronunciation is mocked with a ridiculous parody.

PS. If by 1023 you actually mean 1022+1, then it's like this:

Six point zero two three {times|multiplied by} one thousand and twenty-three.

Instead of saying "point" you can say "decimal" but in N. American English it can sound a little too precise.

[Offroad]

Hi Hazar,

have a look at this

Here's a multiplication (146 x 281) together with all its steps, in words that a Brit might have used as he/she was working it out on paper before the days of pocket calculators.

00146
x0281
------
29200
11680
00146
------
41026

A hundred and forty-six times two hundred and eighty-one.

beginning: Put down two noughts. Two sixes are twelve; put down two and carry one; two fours are eight and one are nine; two ones are two.

next line: Put down one nought. Eight sixes are forty-eight; put down eight and carry four; eight fours are thirty-two and four is thirty-six; put down six and carry three; eight ones are eight and three is eleven.

next line: One times 146 is 146.

addition: Six and nought are nought is six; eight and four and nought is twelve; put down two and carry one; six and two are eight and one is nine and one is ten; put down nought and carry one; none and one are ten and one is eleven; put down one and carry one; two and one are three and one are four.

total: forty-one thousand and twenty-six

and this thread:

Reading an equation!
http://www.usingenglish.com/forum/as...-equation.html