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  1. #1

    Question Wanna translate something for me?

    I don't get this sentnece

    for the line of best fit in the least-squres method:
    the sum of the residuals is zero
    the sume of the squares of the residuals has the least possible value. (I don't get this)

  2. Raymott's Avatar
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    #2

    Re: Wanna translate something for me?

    Quote Originally Posted by hugsandkisses View Post
    I don't get this sentnece

    for the line of best fit in the least-squres method:
    the sum of the residuals is zero
    the sume of the squares of the residuals has the least possible value. (I don't get this)
    If you have a line running through a set of points, it's supposed to represent the trend or the average tendency of the values related to the points.
    If you have two lines running through a set of points, how do you know which is the closest? (which is the best fit)?
    This is what you do:
    For each point, you measure the distance from the line A - this is the "residual".
    You square each residual, ie. multiply it by itself. (This gives a positive number).
    You add up all the residuals.
    This gives you the sum of the squares of the residuals for line A.
    You then do the same for line B.
    Whichever has the lowest value (the least possible value; closest to zero) is the best fit.

    Note that you have to square the residuals to make sure that all values are positive. Otherwise a large positive residual could cancel out a large negative residual. Also by squaring, a large negative residual doesn't have any more influence on lowering the sum, than a large positive residual. Also, by squaring (rather than, say, by taking the absolute value of the residuals), a point a long way from the line has proportionally more effect on the sum).

    Now, let's assume that all the points actually lie on the line. The value of each residual is 0, squared it is 0, and the sum of squares of the residuals is 0. That is the lowest possible value. And that is the best possible fit.
    Last edited by Raymott; 30-Sep-2008 at 03:57.

  3. #3

    Re: Wanna translate something for me?

    Great effort! Thanks!

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