philo2009
Senior Member
- Joined
- Jan 16, 2009
- Member Type
- Academic
- Native Language
- British English
- Home Country
- UK
- Current Location
- Japan
I didn't think the point I was making was so difficult to get. I thought it quite apparent.
M.
No doubt. Sadly, however it was, and is, not.
Since BrE is, by definition, a sub-group of what you (and only you) call 'E', to deny that something true of E is not true of BrE is a contradiction in terms.
The only meaningful distinction to be drawn, by the lights of most, with BrE is AmE.